bài 1 : tính
a)\(\frac{-5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\) b) \(\left(\frac{3}{9}-\frac{9}{18}\right)+\frac{3}{6}-\left(\frac{1}{3}-\frac{1}{2}\right)-\frac{5}{15}\) c) \(\frac{9}{18}+\frac{16}{32}-\frac{12}{46}-\frac{9}{17}\) d) \(\left(\frac{14}{18}+\frac{-16}{27}\right)-\left(\frac{2}{3}-\frac{5}{15}\right)\)
Cho S= \(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{16}+\frac{1}{17}+\frac{1}{18}+\frac{1}{19}+\frac{1}{20}\)
So sánh S với \(\frac{1}{2}\)
Tính nhanh giá trị biểu thức sau:
a) \(-\frac{9}{10}\cdot\frac{5}{14}+\frac{1}{10}\cdot\left(-\frac{9}{2}\right)+\frac{1}{7}\cdot\left(-\frac{9}{10}\right)\)
b)\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}+\frac{1}{11}\right)\cdot132\)
c)\(-\frac{2}{3}\cdot\left(\frac{8}{9}\cdot\frac{8}{13}-\frac{8}{27}\cdot\frac{3}{13}+\frac{4}{3}\cdot\frac{22}{39}\right)\)
cho s=\(\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\)
chung minh rang 1<s<2 tu do suy ra s ko phai la so tu nhien
Cho A = \(\frac{1}{5^2}+\frac{2}{5^3}+\frac{3}{5^4}+...........+\frac{n}{5^{n+1}}+........+\frac{11}{5^{12}}\)với n \(\in\)N . Chứng minh rằng A < \(\frac{1}{6}\)
Thực hiện phép tính ( hợp lí nếu có ) :
a) ( \(\frac{1}{4}\) + \(\frac{-5}{13}\) ) + ( \(\frac{2}{11}\) + \(\frac{-8}{13}\) + \(\frac{3}{4}\) )
b) ( \(\frac{21}{31}\) + \(\frac{-16}{7}\) ) + ( \(\frac{44}{53}\) + \(\frac{10}{31}\) ) + \(\frac{9}{53}\)
c) \(\frac{\frac{9}{45}-\frac{4}{13}-\frac{1}{3}}{\frac{3}{13}-\frac{1}{15}+\frac{2}{3}}\)
Cho A=\(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{98}-\frac{1}{99}\)
CMR:0,2<A<0,4
bài 1 : sắp xếp theo thứ tự tăng dần : \(\frac{1}{2};\frac{1}{3};\frac{1}{38};\frac{-1}{12};\frac{-7}{9};\frac{-6}{9};0;\frac{9}{11};\frac{3}{2}\)
thực hiện các phép tính sau
a) \(\frac{\left(\frac{13}{84}.1,4-2,5.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0,1}{70,5-528:7\frac{1}{2}}\)
cần gấp !!!!!!!!!!!!!
