\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(A=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(A=\left(6-5-3\right)+\left(-\frac{2}{3}-\frac{5}{3}+\frac{7}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2+0-\frac{1}{2}\)
\(=\left(-2\right)+\left(-\frac{1}{2}\right)\)
\(=-\frac{5}{2}\)
^...^ 
^_^ Bài làm có gì ko hiểu bạn cứ hỏi mk nhé ^_^
A=6-\(\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}+\frac{5}{2}\)
A=\(\left(6-5-3\right)+\left(\frac{2}{3}-\frac{5}{3}-\frac{7}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}+\frac{5}{2}\right)\)
A=-2+\(\frac{-14}{3}+\frac{9}{2}\)
A=\(\frac{-12}{6}+\frac{-28}{6}+\frac{27}{6}\)
A=\(\frac{-13}{6}\)
Vậy A=\(\frac{-13}{6}\)