Question

Cho a > b . Tính \(\left|s\right|\) biết : S = -(a-b-c) + ( -c + b + a ) - ( a+ b)

Answer 1

\(S=-\left(a-b-c\right)+\left(-c+b+a\right)-\left(a+b\right)\)

\(=-a+b+c-c+b+a-a-b\)

\(=-a\)

\(\Rightarrow\left|S\right|=\left|-a\right|=a\)

Vậy ................

Answer 2

ta có : S=-(a-b-c)+(-c+b+a)-(a+b)

=-a+b+c-c+b+a-a-b

=-a\(\Rightarrow\)\(\left|S\right|\)=\(\left|-a\right|\)=a