b. A \(⋮\) B \(\Leftrightarrow\) 2x-1 \(⋮\) x-3
Ta có: 2x-1 = 2(x-3) +6-1 = 2(x-3)+5
Để 2x-1 \(⋮\) x-3 thì 5 \(⋮\) x-3
\(\Rightarrow x-3\) \(\in\) Ư(5) \(\Rightarrow\) x-3 \(\in\left\{-5;-1;1;5\right\}\)
Ta có bảng sau:
x-3 |
-5 | -1 | 1 | 5 |
x | -2 | 2 | 4 | 8 |
Vậy x \(\in\left\{-2;2;4;8\right\}\)