\(n_{Fe}=x;n_{Al}=y\\ n_{H_2SO_4}=2.0,2=0,4\left(mol\right)\)
\(PTHH:Fe+H_2SO_4\rightarrow FeSO_4+H_2\)
\(PTHH:2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(hpt_{\left(1\right)}:\left\{{}\begin{matrix}56x+27y=8,3\\22,4\left(x+1,5y\right)=5,6\end{matrix}\right.\Leftrightarrow x=y=0,1\)
\(n_{H_2SO_4.du}=0,4-\left(x+3y\right)=0,4-0,4=0\left(mol\right)\)
\(\rightarrow H_2SO_4.k.du\)
\(PTHH:FeSO_4+Ba\left(OH\right)_2\rightarrow Fe\left(OH\right)_2\downarrow+BaSO_4\downarrow\)
\(PTHH:Al_2\left(SO_4\right)_3+3Ba\left(OH\right)_2\rightarrow3BaSO_4\downarrow+2Al\left(OH\right)_3\downarrow\)
\(n_{Ba\left(OH\right)_2}=1.0,42=0,42\left(mol\right)\)
\(n_{Ba\left(OH\right)_2.du}=0,42-\left(0,1+\frac{0,1}{2}.3\right)=0,17\left(mol\right)\)
→ Tác dụng tiếp với \(Al\left(OH\right)_3\)
\(PTHH:2Al\left(OH\right)_3+Ba\left(OH\right)_2\rightarrow Ba\left(AlO_2\right)_2+4H_2O\)
\(\Rightarrow n_{Al\left(OH\right)_3}=2.n_{Ba\left(OH\right)_2}=2.0,17=0,34\left(mol\right)\)
\(\Rightarrow\sum_{n_{Al\left(OH\right)_3}}=0,34+0,1.2=0,54\left(mol\right)\)
\(PTHH:Fe\left(OH\right)_2\underrightarrow{t^o}FeO+H_2O\)
\(PTHH:2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(m_{kt}=0,1.90+0,54.78=51,12\left(g\right)\)
\(m_1=0,1.72+\frac{0,54}{2}.102=34,74\left(g\right)\)