nCO2= \(\dfrac{4,48}{22,4}\)=0,2mol
mCO2=0,2.44=8.8(g)
Ta có PTHH:
3CO2+2NaOH--->2NaHCO3+CO2+H2
mdung dịch=400+8,8=408,8(g)
nNaHCO3=\(\dfrac{0,2.2}{3}\)=0,13mol
mNaHCO3=0,13.72=9,36(g)
C%=\(\dfrac{9,36}{408,8}.100\%=\)2,28%
mik lấy xấp xỉ , sai nhớ bảo OK