a) \(\left(\dfrac{-1}{2}\right)^4+\left|-\dfrac{2}{3}\right|-2007^0\)
\(=\dfrac{1}{16}+\dfrac{2}{3}-1\)
\(=\dfrac{3}{48}+\dfrac{32}{48}-\dfrac{48}{48}\)
\(=\dfrac{-13}{48}\)
b)\(4\left(\dfrac{-1}{2}\right)^3+\left|\dfrac{1}{2}\right|:5\)
\(=4.\dfrac{-1}{8}+\dfrac{1}{2}:5\)
\(=\dfrac{-4}{8}+\dfrac{1}{2}.\dfrac{1}{5}\)
\(=\dfrac{-1}{2}+\dfrac{1}{10}\)
\(=\dfrac{-5}{10}+\dfrac{1}{10}\)
\(=\dfrac{-4}{10}\)
\(=\dfrac{-2}{5}\)
a) (\(\dfrac{-1}{2}\))4 + | - \(\dfrac{2}{3}\) | - 20070
= (\(\dfrac{-1}{2}\))4 + \(\dfrac{2}{3}\) - 1
= \(\dfrac{1}{8}\) + \(\dfrac{2}{3}\) - 1
= \(\dfrac{3}{24}\) + \(\dfrac{16}{24}\) - 1
= \(\dfrac{19}{24}\) - 1
= \(\dfrac{19}{24}\) - \(\dfrac{24}{24}\)
= \(\dfrac{-5}{24}\)
b) 4(\(\dfrac{-1}{2}\))3 + | \(\dfrac{1}{2}\) | : 5
= 4. \(\dfrac{-1}{8}\) + \(\dfrac{1}{2}\) : 5
= \(\dfrac{-1}{2}\) + \(\dfrac{1}{2}\) . \(\dfrac{1}{5}\)
= \(\dfrac{-1}{2}\) + \(\dfrac{1}{10}\)
= \(\dfrac{-5}{10}\) + \(\dfrac{1}{10}\)
= \(\dfrac{-2}{5}\)
~ Yorin ~