Question

Câu 1

a)(-9)+(-3)

b)6.7.5²+42.75

c)4529-(186+4529)

Câu 2

a)x-7=15

b)9+4.(x-5)=17

c)(x-3)³=27

Answer 1

Câu 1

a)(-9)+(-3) = -9 - 3 = -12

b)6.7.5²+42.75 = 42. 25 + 42. 75 = 42(25 + 75) = 42. 100 = 4200

c)4529-(186+4529) = 4529 - 186 - 4529 = -186

Câu 2

a)x-7=15

<=> x = 15 + 7

<=> x = 22

b)9+4.(x-5)=17

<=> 9 + 4x - 20 = 17

<=> 4x = 28

<=> x = 7

c)(x-3)³=27

<=> (x - 3)³ = 3³

=> x - 3 = 3

<=> x = 6

Answer 2

Câu 1: 

a) Ta có: (-9)+(-3)

=-(9+3)

=-12

b) Ta có: \(6\cdot7\cdot5^2+42\cdot75\)

\(=6\cdot7\cdot5^2+6\cdot7\cdot5^2\cdot3\)

\(=6\cdot7\cdot5^2\cdot\left(1+3\right)\)

\(=6\cdot7\cdot25\cdot4\)

\(=42\cdot100=4200\)

c) Ta có: 4529-(186+4529)

=4529-186-4529

=-186

Câu 2: 

a) Ta có: x-7=15

\(\Leftrightarrow x=15+7\)

hay x=22

Vậy: x=22

b) Ta có: \(9+4\left(x-5\right)=17\)

\(\Leftrightarrow9+4x-20=17\)

\(\Leftrightarrow4x-11=17\)

\(\Leftrightarrow4x=28\)

hay x=7

Vậy: x=7

c) Ta có: \(\left(x-3\right)^3=27\)

\(\Leftrightarrow\left(x-3\right)^3=3^3\)

\(\Leftrightarrow x-3=3\)

hay x=6

Vậy: x=6