3x+1+(3x+1−xx2+2x+1):2x2+3xx+1]:1+3xx2+x" id="MathJax-Element-1-Frame" role="presentation" style="box-sizing: border-box; display: inline-block; line-height: 0; font-size: 20.34px; word-wrap: normal; word-spacing: normal; white-space: nowrap; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;" tabindex="0">
\(B=\left[\dfrac{3}{x+1}+\left(\dfrac{3}{x+1}-\dfrac{x}{\left(x+1\right)^2}\right):\dfrac{2x^2+3x}{x+1}\right]:\dfrac{1+3x}{x^2+x}\)
\(B=\left(\dfrac{3}{x+1}+\dfrac{3x+3-x}{\left(x+1\right)^2}\times\dfrac{x+1}{x\left(2x+3\right)}\right)\times\dfrac{x\left(x+1\right)}{1+3x}\)
3x+1+(3x+1−xx2+2x+1):2x2+3xx+1]:1+3xx2+x" role="presentation" style="box-sizing: border-box; display: inline-block; line-height: 0; font-size: 20.34px; word-wrap: normal; word-spacing: normal; white-space: nowrap; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;" tabindex="0">
\(B=\dfrac{1+3x}{x\left(x+1\right)}\times\dfrac{x\left(x+1\right)}{1+3x}\)
\(B=1\)