Question

Bài tập: Giải phương trình

1) 5-3x=6x+7

2)\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)

3) \(\frac{x-1}{x+3}-\frac{x}{x-3}=\frac{4-8x}{x^2-9}\)

Answer 1

3) \(\frac{x-1}{x+3}-\frac{x}{x-3}=\frac{4-8x}{x^2-9}\)

\(\Leftrightarrow\left(x-1\right)\left(x-3\right)-x\left(x+3\right)=4-8x\)

\(\Leftrightarrow x^2-3x-x+3-x^2-3x=4-8x\)

\(\Leftrightarrow x=1\)

Vậy : \(S=\left\{1\right\}\)