Ta có:
\(B=\dfrac{x^2}{x^4+1}\)
\(2B-1=\dfrac{2x^2-x^4-1}{x^4+1}\)
\(2B-1=\dfrac{-\left(x^2-1\right)^2}{x^4+1}\)
Ta có:
\(\dfrac{-\left(x^2-1\right)}{x^4+1}\le0\)
\(\Rightarrow2B-1\le0\)
\(\Leftrightarrow B\le\dfrac{1}{2}\)
dấu "=" xảy ra khi
\(x^2=1\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)