Question

Bài 3: Tính(hợp lí nếu có thể)

a) \(\dfrac{-7}{9}\)+\(\dfrac{5}{12}\)-\(\dfrac{13}{18}\)

b)\(\dfrac{11}{9}\)x\(\dfrac{15}{4}\)-\(\dfrac{11}{4}\)x\(\dfrac{7}{9}\)-\(\dfrac{11}{9}\)x\(\dfrac{5}{4}\)

c)(\(15\dfrac{9}{7}\)+\(6\dfrac{2}{3}\))-\(5\dfrac{5}{9}\)

d)\(\dfrac{5}{6}\)-\(\dfrac{1}{3}\)-\(\dfrac{2}{-18}\)

e)(\(6\dfrac{4}{9}\)+\(3\dfrac{7}{11}\))-\(4\dfrac{4}{9}\)

f)(\(11\dfrac{2}{7}\)+\(3\dfrac{2}{5}\))-\(7\dfrac{2}{7}\)

Answer 1

a: \(=\dfrac{-28}{36}+\dfrac{15}{36}-\dfrac{26}{36}=\dfrac{-39}{36}=\dfrac{-13}{12}\)

b: \(=\dfrac{11}{9}\left(\dfrac{15}{4}-\dfrac{7}{4}-\dfrac{5}{4}\right)=\dfrac{11}{9}\cdot\dfrac{3}{4}=\dfrac{11}{12}\)

c: \(=15+\dfrac{9}{7}+6+\dfrac{2}{3}-5-\dfrac{5}{9}\)

\(=16+\dfrac{88}{63}=\dfrac{1096}{63}\)

d: \(=\dfrac{5}{6}-\dfrac{1}{3}+\dfrac{2}{18}\)

\(=\dfrac{15-6+2}{18}=\dfrac{11}{18}\)