Question

Bài 1: Tính:

A= ((2^12 . 3^5 - 4^6 . 9^3 ) / 9( 2^2 . 3 )^6 + (8^4 . 3^5))) - ((5^10 . 7^3 - 25^2 . 49^2) / (( 125 . 7 )^3 + 5^9 . 14^3))

B= (2^9 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^0 + 12^10)