a, \(\left(350-x\right):2^5=216^0+7\)
\(\Rightarrow\left(350-x\right):32=1+7=8\)
\(\Rightarrow350-x=8.32=256\)
\(\Rightarrow x=350-256=94\)
Vậy........
b, \(\left(6x-39\right).28=5628\)
\(\Rightarrow6x-39=201\Rightarrow6x=240\)
\(\Rightarrow x=40\)
Vậy............
c, \(5^{2x+1}=125\)
\(\Rightarrow5^{2x+1}=5^3\)
Vì \(5\ne-1;5\ne0;5\ne1\) nên \(2x+1=3\)
\(\Rightarrow2x=2\Rightarrow x=1\)
Vậy.........
Chúc bạn học tốt!!!
a) \(\left(350-x\right):2^5=216^0+7\)
\(\left(350-x\right):32=1+7\)
\(\left(350-x\right):32=8\)
\(350-x=8.32\)
\(350-x=256\)
\(x=350-256\)
\(x=94\left(TM\right)\)
Vậy \(x=94\) là giá trị cần tìm
b) \(\left(6x-39\right).28=5628\)
\(6x-39=5628:28\)
\(6x-39=201\)
\(6x=201+39\)
\(6x=240\)
\(x=240:6\)
\(x=40\left(tm\right)\)
Vậy \(x=40\) là giá trị cần tìm
c) \(5^{2x+1}=125\)
\(5^{2x+1}=5^3\)
\(\Leftrightarrow2x+1=3\)
\(2x=3-1\)
\(2x=2\)
\(x=2:2\)
\(x=1\left(tm\right)\)
Vậy \(x=1\) là giá trị cần tìm