Tick mình nha
a, 4(x-3) = \(7^2-1^{10}=49-1=48\)
hay 4x-12= 48 \(\Rightarrow x=15\)
b,\(3^2\left(x+4\right)-5^2=5.2^2\Rightarrow9\left(x+4\right)-25=20\Rightarrow9\left(x+4\right)=45\Rightarrow x+4=5\Rightarrow x=1\)
c , 0:x = 0 \(\Leftrightarrow x\ne0\) thì luôn thỏa mãn
a) \(4\left(x-3\right)=7^2-1^{10}\)
\(\Rightarrow4x-12=49-1\)
\(\Leftrightarrow4x-12=48\)
\(\Leftrightarrow4x=48+12\)
\(\Leftrightarrow4x=60\)
\(\Rightarrow x=15\)
Vậy \(x=15\)
b) \(3^2\left(x+4\right)-5^2=5\cdot2^2\)
\(\Rightarrow9\left(x+4\right)-25=5\cdot4\)
\(\Leftrightarrow9x+36-25=20\)
\(\Leftrightarrow9x+11=20\)
\(\Leftrightarrow9x=20-11\)
\(\Leftrightarrow9x=9\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
c) \(0:x=0\)
\(\Rightarrow0:x=0\left(đk:x\ne0\right)\)
\(\Rightarrow\) x \(\in\) R \(\forall x\ne0\)
a) 4(x-3)=72-110
4x-12=49-1
4x-12=48
4x=48+12
4x=60
x=60:4
x=15
b) 32(x+4)-52=5.22
9(x+4)-25=5.4
9(x+4)-25=20
9(x+4)=20+25
9(x+4)=45
x+4=45:9
x+4=5
x=5-4
x=1
c)0:x=0
x=0:0
x=0
Bài 1 :
a) \(4\left(x-3\right)=7^2-1^{10}\)
\(4\left(x-3\right)=14-1\)
\(4\left(x-3\right)=13\)
\(x-3=13:4\)
\(x-3=\dfrac{13}{4}\)
\(x=\dfrac{13}{4}+3\)
\(x=\dfrac{25}{4}\)
Vậy \(x=\dfrac{25}{4}\) là giá trị cần tìm
b) \(3^2\left(x+4\right)-5^2=5.2^2\)
\(9\left(x+4\right)-25=20\)
\(9\left(x+4\right)=20+25\)
\(9\left(x+4\right)=45\)
\(x+4=45:9\)
\(x+4=5\)
\(x=5-4\)
\(x=1\)
Vậy \(x=1\) lsf giá trị cần tìm
c) \(0:x=0\)
\(\Rightarrow\) \(x\) thỏa mãn với mọi giá trị \(\left(x\ne0\right)\)