Bài 1 : Giải các phương trình sau :
1) x – 8 = 3 – 2(x+ 4)
2) 2(x + 3) – 3(x – 1) = 2
3) 4(x – 5) – (3x – 1) = x – 19
4) 7 – ( x – 2) = 5(2x – 3)
5) 32 – 4(0,5y – 5) = 3y + 2
6) 3(x – 1) – x = 2x – 3
7) x2 + 2x – 4 = –12 + 3x + \(x^2\)
8) x( x – 1) – x(x + 3) = 15
9) x( x – 1) = x(x + 3)
10) (x–1)(x +3) – (x+2)(x–3) = 0
11) (x–2)(x –5) – (x–3)(x–4) = 0
12) (3x – 2)(4x + 3) = 2x(6x – 1)
13) \(4x^2\) – (2x + 1)(2x – 1) = 0
14) (4x–5)(x+3) = (2x – 3)(7+2x)
15) (x + 3)(x – 2) = (x + 1)2
16) (x+7)(x–7) + \(x^2\) – 2 = 2(\(x^2\)+5 )
17) \(\left(x-1\right)^2\) + \(\left(x+3\right)^2\) = 2(x– 2)(x+2)
18) \(\left(x-5\right)^2\) = \(\left(x+3\right)^2\) + 2
Mình đang cần , các bạn giúp mình với ạ !!!
1,\(x-8=3-2\left(x+4\right)\)
\(\Leftrightarrow\)\(x-8=3-2x-8\)
\(\Leftrightarrow x-8-3+2x+8=0\)
\(\Leftrightarrow3x-3=0\)
\(\Leftrightarrow3x=3\)
\(\Leftrightarrow x=1\)
Vậy \(S=\left\{1\right\}\)
2,\(2\left(x+3\right)-3\left(x-1\right)=2\)
\(\Leftrightarrow2\left(x+3\right)-3\left(x-1\right)-2=0\)
\(\Leftrightarrow2x+6-3x+3-2=0\)
\(\Leftrightarrow-x+7=0\) \(\Leftrightarrow-x=-7\)
\(\Leftrightarrow x=7\)
Vậy \(S=\left\{1\right\}\)
3,\(4\left(x-5\right)-\left(3x-1\right)=x-19\)
\(\Leftrightarrow4x-20-3x+1-x+19=0\)
\(\Leftrightarrow0x+0=0\) (pt vô số nghiệm)
Vậy S=R
4,\(7-\left(x-2\right)=5\left(2x-3\right)\)
\(\Leftrightarrow7-x+2-10x+15=0\)
\(\Leftrightarrow24-11x=0\)
\(\Leftrightarrow11x=24\)
\(\Leftrightarrow x=\frac{24}{11}\)
Vậy \(S=\left\{\frac{24}{11}\right\}\)
mấy bạn ơi , ai giúp mình nốt mấy câu còn lại với ạ
