B1
a,\(\dfrac{7}{3}\).\(\dfrac{37}{5}\)-\(\dfrac{7}{3}\).\(\dfrac{32}{5}\)
b, 3:+\(\left(-\dfrac{3}{2}\right)^2\)+ \(\dfrac{1}{9}\).\(\sqrt{36}\)
c,\(\left(-2\right)^2\) + \(\sqrt{36}\)-\(\sqrt{9}\)+\(\sqrt{25}\)
d, \(\left(-\dfrac{2}{3}+\dfrac{3}{7}\right)\) : \(\left(-\dfrac{1}{3}+-\dfrac{4}{7}\right):\dfrac{4}{5}\)
B2
a, \(\dfrac{3}{4}\)+\(\dfrac{1}{4}\):x = \(\dfrac{1}{2}\)
b, -8 + 2 . |2x-3| =4
c, |x - \(\dfrac{1}{3}\)|- \(\sqrt{\dfrac{1}{6}}\)=\(\sqrt{\dfrac{1}{9}}\)
B1
a. = 7/3. ( 37/5 - 32/5)
= 7/3 . 1
= 7/3
Phần b có gì đó sai sao lại có 3:+
c. = 4 + 6 - 3 + 5
= 12
d. = -5/21 : -19/21 : 4/5
= 25/76
B2
a. 1/4 : x =1/2 - 3/4
x = -1/4
x = 1/4 : -1/4
x = -1
b. 2 . | 2x - 3 | = 4 - (-8)
2 . | 2x - 3| = 12
| 2x - 3 | = 12:2
| 2x - 3 | = 6
| x - 3 | = 6:2
| x - 3 | = 3
=> x - 3 = +- 3
* x - 3 = 3
x = 6
* x - 3 = -3
x = 0
Chúc bạn vui vẻ 
b. = 3 : 9/4 + 1/9 .6
= 4/3 + 2/3
= 2
sr mik nhầm phải là
3:\(\left(-\dfrac{3}{2}\right)^2\)+\(\dfrac{1}{9}\).\(\sqrt{36}\)