https://i.imgur.com/gxCqrM4.jpg
Chương 3: PHƯƠNG TRÌNH, HỆ PHƯƠNG TRÌNH
Các câu hỏi tương tự
giải các phương trình hệ phương trình sau :
1, ( 2x-1)4 + ( 2x + 3 ) 4 626
2, (3x + 2 ) 4 + ( 3x +4)4 16
3, 16( x - 1 )4 + (2x +3 )4 2
4 , 256( x - 2 )4 + ( 4x + 2 ) 4 2
5 , ( x - 2 ) ( x - 1 ) ( x + 3 ) (x + 4 ) 24
6 , ( x2 + 3x +2 ) ( x2 + 7x + 12 ) 24
7 ( x2 - 1 ) ( x + 3 ) ( x + 5 ) 9
8 , x ( x2 - 4 ) ( x + 4 ) 18
9 , ( x2 - 3x + 2 ) ( x2 - 9x +20 ) 4
10 , ( x+1 ) ( x + 2 ) ( x + 3 ) ( x + 4 ) 3
11,( x + 4 ) ( x+ 5 ) ( x + 7 ) ( x + 8 ) 4
12 , x ( x + 1 ) (...
Đọc tiếp
giải các phương trình hệ phương trình sau :
1, ( 2x-1)4 + ( 2x + 3 ) 4 = 626
2, (3x + 2 ) 4 + ( 3x +4)4 = 16
3, 16( x - 1 )4 + (2x +3 )4 = 2
4 , 256( x - 2 )4 + ( 4x + 2 ) 4 = 2
5 , ( x - 2 ) ( x - 1 ) ( x + 3 ) (x + 4 ) =24
6 , ( x2 + 3x +2 ) ( x2 + 7x + 12 ) = 24
7 ( x2 - 1 ) ( x + 3 ) ( x + 5 ) = 9
8 , x ( x2 - 4 ) ( x + 4 ) = 18
9 , ( x2 - 3x + 2 ) ( x2 - 9x +20 ) = 4
10 , ( x+1 ) ( x + 2 ) ( x + 3 ) ( x + 4 ) = 3
11,( x + 4 ) ( x+ 5 ) ( x + 7 ) ( x + 8 ) = 4
12 , x ( x + 1 ) ( x + 2 ) ( x + 3 ) = 4
Giải hệ phương trình sau :
\(\begin{cases}x^5-3x^4+2x^2-2x+2\ge0\\x^4-2x^3-x+2=0\\x^2-3x+2=0\\\left(x^2-1\right)\left(x-2\right)=0\end{cases}\)
a,\(\sqrt{5X^2+X+3}-2\sqrt{5x-1}+X^2-3X+3=0\)
b,\(^{X^2-X-4+3X\sqrt{5-3X^2}=0}\)
giải các phương trình sau:
a, 2x4+3x3+5x2+3x+2=0
b,x4-8x3-3x2+32x+4=0
c,2x2+x+2-5\(\sqrt{\left(x^2-4\right)\left(x+1\right)}\) =0
ai biết thì giúp với ạ!!
JE
23 tháng 11 2019 lúc 23:22
giải pt
a) \(\left(\sqrt{x+2}+1\right)\left(1+\sqrt{5-x}\right)-5=0\)
b) \(\sqrt{x+1}-\sqrt{4-x}+2\left(\sqrt{x+1}+\sqrt{4-x}\right)^2=17\)
c) \(2\sqrt{x-x^2}=3\left(\sqrt{x}+\sqrt{1-x}-1\right)\)
d) \(\left(3\sqrt{5+2x}-1\right)\left(3\sqrt{5-2x}-1\right)=16\)
Gải phương trình sau
a)\(\sqrt{2x^2+4x+1}=1-x^2-2x\)
b)\(\sqrt{x+4}+\sqrt{x-4}=2x+2\sqrt{x^2-16}\)
c) (x+4)(x+1)-3\(\sqrt{x^2+x+2}=\sqrt{3x^2+3x}\)
1. x^3-x^2+12xsqrt{x-1}+200
2. x^3+sqrt{left(x-1right)^3}9x+8
3. sqrt{2x^2+x+1}+sqrt{x^2-x+1}3x
4. x^6+left(x^3-3right)^33x^5-9x^2-1
5. x^2-6left(x+3right)sqrt{x+1}+14x+3sqrt{x+1}+130
6. x^2-4x+left(x-3right)sqrt{x^2-x+1}-1
7. sqrt{2x-1}+sqrt{5-x}x-2+2sqrt{-2x^2+11x-5}
8. sqrt{5x+11}-sqrt{6-x}+5x^2-14x-600
9. x^2+6x+83sqrt{x+2}
10. 2x^2+3x-2left(2x-1right)sqrt{2x^2+x-3}
11. sqrt{x+1}+sqrt{4-x}-sqrt{left(x+1right)left(4-xright)}1
12. x^2-sqrt{x^2-4x}4left(...
Đọc tiếp
1. \(x^3-x^2+12x\sqrt{x-1}+20=0\)
2. \(x^3+\sqrt{\left(x-1\right)^3}=9x+8\)
3. \(\sqrt{2x^2+x+1}+\sqrt{x^2-x+1}=3x\)
4. \(x^6+\left(x^3-3\right)^3=3x^5-9x^2-1\)
5. \(x^2-6\left(x+3\right)\sqrt{x+1}+14x+3\sqrt{x+1}+13=0\)
6. \(x^2-4x+\left(x-3\right)\sqrt{x^2-x+1}=-1\)
7. \(\sqrt{2x-1}+\sqrt{5-x}=x-2+2\sqrt{-2x^2+11x-5}\)
8. \(\sqrt{5x+11}-\sqrt{6-x}+5x^2-14x-60=0\)
9. \(x^2+6x+8=3\sqrt{x+2}\)
10. \(2x^2+3x-2=\left(2x-1\right)\sqrt{2x^2+x-3}\)
11. \(\sqrt{x+1}+\sqrt{4-x}-\sqrt{\left(x+1\right)\left(4-x\right)}=1\)
12. \(x^2-\sqrt{x^2-4x}=4\left(x+3\right)\)
13. \(x^2-x-4=2\sqrt{x-1}\left(1-x\right)\)
14. \(\frac{1}{\sqrt{x}+1}+\frac{1}{\sqrt{x}-1}=1\)
15. \(\sqrt{2x^2+3x+2}+\sqrt{4x^2+6x+21}=11\)
16. \(\sqrt{x+3+3\sqrt{2x-3}}+\sqrt{x-1+\sqrt{2x-1}}=2\sqrt{2}\)
17. \(\left(x-2\right)^2\left(x-1\right)\left(x-3\right)=12\)
18. \(2x^2+\sqrt{x^2-2x-19}=4x+74\)
19. \(x^4+x^2-20=0\)
20. \(x+\sqrt{4-x^2}=2+3x\sqrt{4-x^2}\)
21. \(\left(x^2+x+1\right)\left(\sqrt[3]{\left(3x-2\right)^2}+\sqrt[3]{3x-2}+1\right)=9\)
22. \(\sqrt{x^2-3x+5}+x^2=3x+7\)
23. \(x^2+6x+5=\sqrt{x+7}\)
24. \(\frac{2x^2-3x+10}{x+2}=3\sqrt{\frac{x^2-2x+4}{x+2}}\)
25. \(5\sqrt{x-1}-\sqrt{x+7}=3x-4\)
26. \(2\left(x^2+2\right)=5\sqrt{x^3+1}\)
27. \(\sqrt{x-1}+\sqrt{5-x}-2=2\sqrt{\left(x-1\right)\left(5-x\right)}\)
28. \(x^2+\frac{9x^2}{\left(x-3\right)^2}=40\)
29. \(\frac{26x+5}{\sqrt{x^2+30}}+2\sqrt{26x+5}=3\sqrt{x^2+30}\)
30. \(\frac{\sqrt{27+x^2+x}}{2+\sqrt{5-\left(x^2+x\right)}}=\frac{\sqrt{27+2x}}{2+\sqrt{5-2x}}\)
JE
22 tháng 10 2019 lúc 16:55
Giải pt:
a) \(x\left(x-4\right)\sqrt{-x^2+4x}+\left(x-2\right)^2=2\)
b) \(\left(x^2+1\right)^2=5-x\sqrt{2x^2+4}\)
c) \(2x^2+3x-14=2\sqrt[3]{2x^2+3x-10}\)
d) \(6x^2+2x+\sqrt[3]{3x^2+x+4}-10=0\)
e) \(\left(x+4\right)\left(x+1\right)-3\sqrt{x^2+5x+2}=6\)
a) 3x3 +2x2 - 2x -1 =0
b) x4 + 4x3 + 3x2 + 2x -1 =0
c) x3 - 6x2 + 7x + 2 =0
d) 2x4 + x3 - 8x2 - x + 6 =0
giúp mk vs