a) ĐKXĐ: \(x\ne\text{5}\)
\(\frac{x-3}{x-5}=\frac{5}{9}\)
\(\Rightarrow9\left(x-3\right)=5\left(x-5\right)\)
\(\Leftrightarrow9x-27=5x-25\)
\(\Leftrightarrow4x=2\)
\(\Leftrightarrow x=\frac{1}{2}\left(TM\right)\)
Vậy \(x=\frac{1}{2}\)
b) ĐKXĐ: \(x\ne5;x\ne9\)
\(\frac{x-3}{x-5}=\frac{x-8}{x-9}\)
\(\Rightarrow\left(x-3\right)\left(x-9\right)=\left(x-5\right)\left(x-8\right)\)
\(\Leftrightarrow x^2-9x-3x+27=x^2-8x-5x+40\)
\(\Leftrightarrow x^2-12x+27=x^2-13x+40\)
\(\Leftrightarrow x=13\left(TM\right)\)
Vậy \(x=13\)
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