ta có: nCuO= \(\dfrac{16}{80}\)= 0,2( mol)
PTPU
CuO+ H2SO4\(\rightarrow\) CuSO4+ H2O
..0,2....0,2...............0,2................. ( mol)
\(\Rightarrow\) mH2SO4= 0,2. 98= 19,6( g)
\(\Rightarrow\) C% H2SO4= \(\dfrac{19,6}{200}\). 100%= 9,8%
CuSO4+ 2NaOH\(\rightarrow\) Na2SO4+ Cu(OH)2\(\downarrow\)
..0,2...........................0,2...............0,2....... ( mol)
\(\Rightarrow\) CM Na2SO4= \(\dfrac{0,2}{0,2}\)= 1M
a= mCu(OH)2= 0,2. 98= 19,6( g)