Question

a) Tính :

1)\(5\frac{3}{8}-\frac{40}{5}(x-1)=4\frac{3}{8}\)

Answer 1

\(5\frac{3}{8}-\frac{40}{5}\left(x-1\right)=4\frac{3}{8}\)

\(\Leftrightarrow\frac{43}{8}-\frac{40}{5}.\left(x-1\right)=\frac{35}{8}\)

\(\Leftrightarrow\frac{40}{5}\left(x-1\right)=1\)

\(\Leftrightarrow40\left(x-1\right)=5\)

\(\Leftrightarrow40x=45\)

\(\Leftrightarrow x=\frac{9}{8}\)

Vậy \(x=\frac{9}{8}\)

Answer 2

Ta có :

=> \(\frac{40}{5}\left(x-1\right)\) = \(5\frac{3}{8}\) - \(4\frac{3}{8}\)

=> 8x - 8 = 1

=> 8x = 9

=> x = \(\frac{9}{8}\)

Answer 3

Ta có: \(5\frac{3}{8}-\frac{40}{5}\left(x-1\right)=4\frac{3}{8}\)

\(\Leftrightarrow\frac{43}{8}-8x+8=\frac{35}{8}\)

\(\Leftrightarrow\frac{43}{8}-8x+8-\frac{35}{8}=0\)

\(\Leftrightarrow-8x+9=0\)

\(\Leftrightarrow-8x=-9\)

hay \(x=\frac{9}{8}\)

Vậy: \(x=\frac{9}{8}\)