Ta có: \(\widehat{xOy}+\widehat{yOz}=180^0\) (vì 2 góc kề bù)
Vì tia \(Ot\) nằm giữa 2 tia \(Oy\) và \(Oz\left(gt\right)\)
=> \(\widehat{yOz}=\widehat{zOt}+\widehat{yOt}.\)
=> \(\widehat{xOy}+\widehat{zOt}+\widehat{yOt}=180^0\)
=> \(20^0+95^0+\widehat{yOt}=180^0\)
=> \(115^0+\widehat{yOt}=180^0\)
=> \(\widehat{yOt}=180^0-115^0\)
=> \(\widehat{yOt}=65^0.\)
Vậy \(\widehat{yOt}=65^0.\)
Chúc bạn học tốt!