=> 5x^2 - 2x + 10=3x^2 + 10x - 8
=> 2x^2 -12x +18 = 0
=> 2(x^2 - 6x +9) = 0
=> 2(x - 3)^2 = 0
=> x - 3 = 0
=> x = 3
Phương trình bậc nhất một ẩn
Các câu hỏi tương tự
(5x^2 - 2x + 10)^2 = (3x^2 + 10x - 8)^2
1) 4x-10=0 2) 2x^3 + 6x^2 = x^2 + 3x 3) x - 5 = 3 - x 4) (-10x + 5 ) ( 2x - 8 ) = 0
SN
23 tháng 1 2022 lúc 20:10
5,\(\dfrac{x^2-5x-4}{8}\)=\(\dfrac{x+1}{2}\)+\(\dfrac{x^2-10x}{9}\)
6,(x+3)(x-3)=(x-1)(9-x)
7,(x-1)\(^2\)=9(x^2+2x+1)
8,(x^2-5x+8)\(^2\)-(5x-17)\(^2\)
giup em voi a
Giai pt
- \(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2+10x}=\frac{x+25}{2x^2-50}\)
- \(\dfrac{\left(x+2\right)^2}{2x-3}-1=\dfrac{x^2+10}{2x-3}\)
1. dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4}dfrac{2left(2x+1right)}{7}-5
2. x-dfrac{3left(x+30right)}{15}-24dfrac{1}{2}dfrac{7x}{10}-dfrac{2left(10x+2right)}{5}
3. 14dfrac{1}{2}-dfrac{2left(x+3right)}{5}dfrac{3x}{2}-dfrac{2left(x-7right)}{3}
4. dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}
5. dfrac{3left(2x-1right)}{4}-dfrac{3x+1}{10}+1dfrac{2left(3x+2right)}{5}
6. x-dfrac{3}{17}left(2x-1right)dfrac{7}{34}left(1-2xright)+dfrac{10x-3}{2}
7. dfrac{3le...
Đọc tiếp
1. \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
2. \(x-\dfrac{3\left(x+30\right)}{15}-24\dfrac{1}{2}=\dfrac{7x}{10}-\dfrac{2\left(10x+2\right)}{5}\)
3. \(14\dfrac{1}{2}-\dfrac{2\left(x+3\right)}{5}=\dfrac{3x}{2}-\dfrac{2\left(x-7\right)}{3}\)
4. \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
5. \(\dfrac{3\left(2x-1\right)}{4}-\dfrac{3x+1}{10}+1=\dfrac{2\left(3x+2\right)}{5}\)
6. \(x-\dfrac{3}{17}\left(2x-1\right)=\dfrac{7}{34}\left(1-2x\right)+\dfrac{10x-3}{2}\)
7. \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
8. \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
bài 1 giải phương trình
a) (2x+3)^2-3(x-4)(x+4)left(x-2right)^2+1
b)(3x-2) (9x^2+6x+4)-(3x-1) (9x^2+3x+1)x-4
c)x (x-1) -(x-3) (x+4)5x
d) (2x+1)(2x-1)4x(x-7)-3x
bài 2 giải phương trình
a)frac{x}{10}-left(frac{x}{30}+frac{2x}{45}right)frac{4}{5}
b)frac{10x-5}{18}+frac{x+3}{12}frac{7x+3}{6}+frac{12-x}{9}
c)frac{10x+3}{8}frac{7-8x}{12}
d)frac{x+4}{5}-x-5frac{x+3}{3}-frac{x-2}{2}
Đọc tiếp
bài 1 giải phương trình
a) (2x+3)\(^2\)-3(x-4)(x+4)=\(\left(x-2\right)^2\)+1
b)(3x-2) (9x\(^2\)+6x+4)-(3x-1) (9x\(^2\)+3x+1)=x-4
c)x (x-1) -(x-3) (x+4)=5x
d) (2x+1)(2x-1)=4x(x-7)-3x
bài 2 giải phương trình
a)\(\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
b)\(\frac{10x-5}{18}+\frac{x+3}{12}=\frac{7x+3}{6}+\frac{12-x}{9}\)
c)\(\frac{10x+3}{8}=\frac{7-8x}{12}\)
d)\(\frac{x+4}{5}-x-5=\frac{x+3}{3}-\frac{x-2}{2}\)
x+5/x^2-5x - x-5/2x^2+10x=x+25/2x^2-50
Giải pt sau:
a)(x^2-1)(x+2)(x-3)(x-1)(x^2-4)(x+5)
b)(5x^2-2x+10)^2(3x^2+10x-8)^2
c)(x^2+x)^2+4(x^2+x)-120
Giúp mình vs mik cần gấp!help me help me
Đọc tiếp
Giải pt sau:
a)(\(x^2\)-1)(x+2)(x-3)=(x-1)(\(x^2\)-4)(x+5)
b)(\(5x^2\)-2x+10)\(^2\)=(3x\(^2\)+10x-8)\(^2\)
c)(x\(^2\)+x)\(^2\)+4\((x^2+x)\)-12=0
Giúp mình vs mik cần gấp!help me help me
Giải các phương trình sau :
1, 2x (x + 2)^2 - 8x^2 2 (x - 2) (x^2 + 2x +4)
2, 8x (x +3 )^2 - 3x ( x +2)^3 +1
3, dfrac{10x+3}{12} 1 + dfrac{6+8x}{9}
4,dfrac{x-23}{24}+dfrac{x-23}{25}dfrac{x-23}{26}+dfrac{x-23}{27}
5,dfrac{x^2-10x-29}{1971}+dfrac{x^2-10x-27}{1973}dfrac{x^2-10x-1971}{29}+dfrac{x^2-10x-1973}{27}
Giúp mk nha mấy bạn mk đg cần gấp nên mong mấy bạn giúp đỡ
Đọc tiếp
Giải các phương trình sau :
1, 2x (x + 2)\(^2\) - 8x\(^2\) = 2 (x - 2) (x\(^2\) + 2x +4)
2, 8x (x +3 )\(^2\) - 3x = ( x +2)\(^3\) +1
3, \(\dfrac{10x+3}{12}\) = 1 + \(\dfrac{6+8x}{9}\)
4,\(\dfrac{x-23}{24}+\dfrac{x-23}{25}=\dfrac{x-23}{26}+\dfrac{x-23}{27}\)
5,\(\dfrac{x^2-10x-29}{1971}+\dfrac{x^2-10x-27}{1973}=\dfrac{x^2-10x-1971}{29}+\dfrac{x^2-10x-1973}{27}\)
Giúp mk nha mấy bạn mk đg cần gấp nên mong mấy bạn giúp đỡ