\(5\left(x-3\right)-3x+2=0\)
\(\Leftrightarrow5x-15-3x+2=0\)
\(\Leftrightarrow2x-13=0\)
\(\Leftrightarrow2x=13\)
\(\Leftrightarrow x=\dfrac{13}{2}\)
Vậy ......
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Ta có: 5.(x-3)-3x+2=0
\(\Leftrightarrow\) 5x-15-3x+2=0
\(\Leftrightarrow\) (5x-3x) - 15+ 2=0
\(\Leftrightarrow\) 2x-13=0
\(\Leftrightarrow\) 2x = 0+13
\(\Leftrightarrow\) 2x = 13
\(\Leftrightarrow\) x = 13:2
\(\Leftrightarrow\) x = \(\dfrac{13}{2}\)
Vậy x = \(\dfrac{13}{2}\)
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