ta có : \(4^{x-2}+4^{x+1}=1040\Leftrightarrow4^{x-2}\left(1+4^3\right)=1040\)
\(\Leftrightarrow4^{x-2}=\dfrac{1040}{1+4^3}=16=4^2\) \(\Rightarrow x-2=2\Leftrightarrow x=4\) vậy \(x=4\)
ta có : \(4^{x-2}+4^{x+1}=1040\Leftrightarrow4^{x-2}\left(1+4^3\right)=1040\)
\(\Leftrightarrow4^{x-2}=\dfrac{1040}{1+4^3}=16=4^2\) \(\Rightarrow x-2=2\Leftrightarrow x=4\) vậy \(x=4\)
4^x-2+4^x+1=1040
1/x+1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)+(x+4)+1/(x+4)
Tìm x.
\(1,\dfrac{3}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}\left(x+\dfrac{1}{2}\right)=\dfrac{1}{4}\)
\(2,3\left(x-2\right)-4\left(x+2\right)=x+2\)
\(3,4x\left(x-1\right)+4x-2\left(x+1\right)=-2\)
\(4,x\left(x+2\right)-3\left(x-1\right)=3\left(x+1\right)\)
(x+2).(1+x-x ² +x ³-x mũ 4)-(1-x).(1+x+x ² +x ³+ x mũ 4)
c)5^x+1-5^x=20 c)2^x+2^x+4=544 c)4^2x+1+4^2x=80 c)3^2x+2+3^2x+1=108 c)7^x+3-7^x+1=16464
Cho hai đa thức P( x ) = x mũ 2 cộng 5 x mũ 4 trừ 3 x mũ 3 cộng x mũ 2 cộng 4 x mũ 4 + 3 x mũ 3 - x + 5
Q(x) = x - 5 x mũ 3 trừ x mũ 2 trừ x mũ 4 + 4 x mũ 3 trừ x mũ 2 + 3 x - 1
a) 2 mũ 3 : |x-2| =2
b) | 2x + 1 | + | 5x -1 | + 7 mũ 4 = 49
c) | x mũ 3 ( x - 4 )= 5x mũ 2
d) | 2x - 5 | = 2 - x
e) x - | x + 1 | = 4
f) 3x + | 4x + 3 | = 5
Tìm x
A, ( x - 1 )^x+2 = ( x - 1 )^x+4
B, 1/4 × 2/6 × 3/8 × 4/10 × 5/12 ×....× 30/62 × 31/64 = 2^x
tìm x,y biết: |x-1/2|+|x-1/3|+|x-1/4|+|y-1/5|=1/4