\(4+\frac{1}{1+\frac{1}{1+\frac{2}{1+\frac{3}{4}}}}=4+\frac{1}{1+\frac{1}{1+\frac{2}{\frac{7}{4}}}}=4+\frac{1}{1+\frac{1}{1+\frac{8}{7}}}=4+\frac{1}{1+\frac{1}{\frac{15}{7}}}=4+\frac{1}{1+\frac{7}{15}}=4+\frac{1}{\frac{22}{15}}=4+\frac{15}{22}=\frac{103}{22}\)