\(\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}^{ }-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Tính giá trị của biểu thức:
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Tính:
a) \(\frac{\left[\left(-2\right)^2\right]^5}{\left(-2\right)^3\left(-2\right)^2\left(-4\right)^2}\)b) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6}\)rút gon
a,\(\frac{2.5^{22}-9.5^{21}}{25^{10}}\)
b,\(\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
c,\(\frac{\left(\left(-2\right)^2\right)^3.\left(-4\right)^2}{\left(-2\right)^3.\left(-2\right)^2}\)
d,\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
e,\(2^3+3.\left(\frac{1}{8}\right)^0-\left(\frac{1}{2^2}\right).4+\left[\left(-2\right)^2:\frac{1}{2}\right].8\)
f,\(\frac{\left(\frac{2}{5}\right)^7.5^5+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
Rút gọn biểu thức sau theo cách hợp lí:
P= \(\frac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}\)
Tính nhanh
\(\frac{2^5.3^7}{2^4.3^6}\)
\(\frac{16^5.9^{10}}{6^{18}}\)
\(\frac{12^5+12^6}{12^6.12^7}-\frac{12^8-12^9}{12^9-13^{10}}\)
Tính gía trị của các biểu thức sau :
\(a,\frac{205.5^{10}}{100^5} \)
\(b,\frac{\left(0,9\right)^5}{\left(0,3\right)^5}\)
\(c,\frac{6^3+3.6+3^3}{-13}\)
\(d,\frac{4^6.9^5.6^9.120}{8^43^{12}-6^{11}}\)
46x95+69x120/84x312-611=?
\(a,\left(-3\right)^{x+3}=-\frac{1}{27}\)
\(b,\left(-6\right)^{2x+2}=\frac{1}{36}\)
\(c,\left(-3\right)^{x+5}=\frac{1}{81}\)
\(d,\left(\frac{1}{9}^x\right)=\left(\frac{1}{27}\right)^6\)
\(e,\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(f,5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(r,4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(h,\left(\frac{1}{2}-\frac{1}{3}\right).6x+6^{x+2}=6^{10}+6^7\)
nhờ mấy bn giúp mk tối mình nộp rồi
