\(4-3\left(x-1\right)=-9-\left(-1\right)\)
\(\Leftrightarrow4-3\left(x-1\right)=-9+1\)
\(\Leftrightarrow4-3\left(x-1\right)=-8\)
\(\Leftrightarrow-3\left(x-1\right)=-12\)
\(\Leftrightarrow x-1=4\Leftrightarrow x=5\)
Vậy x = 5
Ta có:
\(4-3\left(x-1\right)=-9-\left(-1\right)=-8\Rightarrow4-\left(-8\right)=3\left(x-1\right)\Rightarrow3\left(x-1\right)=12\Rightarrow x-1=4\Rightarrow x=5\)