Question

(3x-\(\dfrac{1}{2}\))mũ 2=\(\dfrac{4}{9}\)

Answer 1

\(\left(3x-\dfrac{1}{2}\right)^2=\dfrac{4}{9}\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(3x-\dfrac{1}{2}\right)^2=\left(\dfrac{2}{3}\right)^2\\\left(3x-\dfrac{1}{2}\right)^2=\left(-\dfrac{2}{3}\right)^2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{1}{2}=\dfrac{2}{3}\\3x-\dfrac{1}{2}=-\dfrac{2}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}3x=\dfrac{7}{6}\\3x=-\dfrac{1}{2}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{18}\\x=-\dfrac{1}{6}\end{matrix}\right.\)

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