\(3^{x-3}=9\)
\(3^{x-3}=3^2\)
x-3=2
x=5
\(3^{x-3}=9\)
\(3^{x-3}=3^2\)
x-3=2
x=5
giúp mình với
9x-2(x-29)=-47
2x-5(x+3)=-75
3x-14=2(x-9)+1
Tìm x:
a) \(\left|x-2\right|=3\)
\(\left|x-1\right|>1\)
\(2< \left|x\right|< 5\)
b) \(-x.\left(x+3\right)=0\)
\(\left(x-2\right).\left(3x-9\right)=0\)
P/s: Giusp với
cmr : (9^m+1)(9^m+2)(9^m+3)(9^m+4) chia hết cho 5 với mọi m thuộc N
Bài 4
1) 8 2/7-(4 2/7-3 4/9)
2) (10 2/9+2 3/5)-6 2/9
3) 11 3/13-(2 4/7+5 3/13)
b) 25 +5(x - 3) = 75
c) 2x- 5 - 7= 9
6) x-1/2=9/2
7) x+5/4=-3/4
8) x+2/7=5/7
9) x-4/3=1/3
10) x+5/2=-7/2
xy+14+2y+7x=-10
xy+5x+y=4
xy+x+y=2
xy-10+5x-3y=2
xy-1=3x+5y+4
3x+4y-xy=15
1) x+1/2=-5/3
2) 1/3-x=3/5
4) x-4/3=-7/9
5) x--7/3=5/6
6) x-1/5=9/10
7) x+5/12=3/8
8) x+5/4=7/6
9) x-2/7=1/35
10) x-2/7=-7/10