Question

(2x + 3)\(_{ }^{^2}\)=25

Answer 1

Mấy bạn làm thiếu rồi

Ta có

\(\left(2x+3\right)^2=25=5^2=\left(-5\right)^2\)

Suy ra \(\left\{{}\begin{matrix}2x+3=5\\2x+3=-5\end{matrix}\right.\)

Suy ra \(\left\{{}\begin{matrix}x=\dfrac{5-3}{2}=1\\x=\dfrac{-5-3}{2}=-4\end{matrix}\right.\)

Vậy x=1 và x=-4

Answer 2

(2x+3)^2=5^2

Suy ra: 2x+3=5, x=4

^-^

Answer 3

\(\left(2x+3\right)^2=5^2\)

\(\Rightarrow2x+3=5\)

\(2x=5-3\)

\(2x=2\)

\(x=1\)

Vậy x = 1

Answer 4

\(\left(2x+3\right)^2=25\)

\(\Rightarrow2x+3=\sqrt{25}=5\)

\(\Rightarrow2x=5-3=2\)

\(\Rightarrow x=2:2=1\)

Answer 5

sorry, X=1 nha ^-^