Question

(2x-1)^2_(x+3)^2=0

 

Answer 1

\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)

\(=>\left(2x-1+x+3\right)\left(2x-1-x-3\right)=0\)

\(=>\left(3x+2\right)\left(x-4\right)=0\)

\(=>\left[{}\begin{matrix}3x+2=0\\x-4=0\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}3x=-2\\x=4\end{matrix}\right.\)

\(=>\left[{}\begin{matrix}x=\dfrac{-2}{3}\\x=4\end{matrix}\right.\)

\(=>x\in\left\{\dfrac{-2}{3};4\right\}\)

 

Answer 2

\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)(sửa đề)

\(\Leftrightarrow\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(3x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\3x+2=0\end{matrix}\right.\)           \(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)