Question

\(2\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)\)

Answer 1

\(2\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left[2\left(x+2\right)-\left(x-2\right)\right]=0\)

\(\Leftrightarrow\left(x+2\right)\left(x+6\right)=0\)

\(\Leftrightarrow\left[\begin{matrix}x+2=0\\x+6=0\end{matrix}\right.\)

\(\Leftrightarrow\left[\begin{matrix}x=-2\\x=-6\end{matrix}\right.\)

Vậy x = -2 hoặc x = -6

Answer 2

cai nay la tim x nha cac bn, co ca = 0 o cuoi nua

i am sorry