\(\frac{2}{5}+\left(\frac{3}{5}+\frac{3}{11}-\frac{3}{17}\right):\left(1+\frac{5}{11}-\frac{5}{17}\right)\)
\(=\frac{2}{5}+\frac{651}{935}:\frac{217}{187}\)
\(=\frac{2}{5}+\frac{3}{5}\)
\(=1.\)
c)
Chúc bạn học tốt!
A=\(\dfrac{1}{4.9}+\dfrac{1}{9.14}+\dfrac{1}{14.19}+...+\dfrac{1}{44.49}+\left(\dfrac{1-3-5-7-...-49}{89}\right)\)
B=\(\dfrac{212.3^5.4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^4.49^2}{\left(125.71^3+59.14^3\right)}\)
C=\(\dfrac{\dfrac{1}{2003}+\dfrac{1}{2004}-\dfrac{1}{2005}}{\dfrac{5}{2003}+\dfrac{5}{2004}-\dfrac{5}{2005}}-\dfrac{\dfrac{2}{2002}+\dfrac{2}{2003}-\dfrac{2}{2004}}{\dfrac{3}{2002}+\dfrac{3}{2003}-\dfrac{3}{2004}}\)
D=\(\left(\dfrac{1,5+1-0,75}{2,5+\dfrac{5}{3}-1,25}\right)+\left(\dfrac{0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}}{-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}}\right):\dfrac{1890}{2005}+115\)
E=13+23+...+103=3025
Tính F=23+42+63+...+203=?
B. Tự luận
I: Đại số:
Bài 1: Thực hiện phép tính
1) 11/24 - 5/41 + 13/24 + 0,5 - 36/41
2) -12 : (3/4 - 5/6)^2
3) 7/23. [(-8/6) - 45/18]
4) \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5) (\(1+\frac{2}{3}-\frac{1}{4}\) ) (\(0,8\:-\frac{3}{4}\) )^2
6) 16\(\frac{2}{7}:\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
7) \((2^2:\frac{4}{3}-\frac{1}{2}\) ) . 6/5 - 17
8) (1/3)^50 .(-9)^25 -2/3:4
9) 3/5: ( -1/15 - 1/6 )+3/5:( -1/3 - 1\(\frac{1}{15}\) )
10) (-6,5).5,7+5,7.(-3,5)
11) 10.√0,01.√16/9+3√49-1/6√4
12) \(\frac{2⁴.2⁶}{\left(2⁵\right)^2}-\frac{2⁵.15^3}{6^3.10^2}\)
Bài 2. Tìm x, biết
1) x/12 - 5/6 = 1/12
2) 2/3 - 1\(\frac{4}{15}x=\frac{-3}{5}\)
3) -2^3 + 0,5x =1,5
Nhiêu đó thôi mik còn thiếu nhiều lắm
1, P = \(\dfrac{\dfrac{1}{2003}+\dfrac{1}{2004}-\dfrac{1}{2005}}{\dfrac{5}{2003}+\dfrac{5}{2004}-\dfrac{5}{2005}}\) - \(\dfrac{\dfrac{2}{2002}+\dfrac{2}{2003}-\dfrac{2}{2004}}{\dfrac{3}{2002}+\dfrac{3}{2003}-\dfrac{2}{2004}}\)
2, Q = ( \(\dfrac{1,5+1-0,75}{2,5+\dfrac{5}{3}-1,25}\) + \(\dfrac{0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}}{-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}}\) ) : \(\dfrac{1980}{3758}\) + 155
3, A = 1.3 + 2.4 + 3.5 +....+ 97.99 + 98.100
4, B = 1.2.3 + 2.3.4. +...+ 48.49.50
5, C = \(\dfrac{1}{1.2.3.4}\) + \(\dfrac{1}{2.3.4.5}\) +...+ \(\dfrac{1}{27.28.29.30}\)
6, D = 1 + \(2^2\) + \(2^4\) + \(2^6\) + .... +\(2^{200}\)
7, E = \(\dfrac{1}{3.5}\)+ \(\dfrac{5}{5.7}\) +...+ \(\dfrac{1}{97.99}\)
bt.1 tính
a )-1/12 - (2 trên 5/8 - 1/3)
b 18/ 39 . (- 1 trên 5/8 ) : (-6 trên 3/4 )
c ) 0,75 -0,6 + 3/7 + 3/15 phần 2 ,75 - 2,2 + 11/7 +11/17
Bài 1 :Thực hiện phép tính :
a) M =(\(\frac{-6}{13}+\frac{15}{26}-\frac{47}{39}-\frac{1}{78}\)) : (\(99\frac{17}{65}-100\frac{5}{52}+\frac{1}{130}\))
b) N = \(\frac{(\frac{3}{5}-0,435+\frac{1}{200}):\left(-0,04\right)}{30,75+\frac{1}{12}+3\frac{1}{6}}\)
c) P = (\(\frac{-5}{6}:\frac{-10}{11}\))+\(\frac{\frac{1}{4}+\frac{5}{8}-\frac{7}{13}}{\frac{-2}{12}-\frac{10}{24}+\frac{14}{39}}\)
Bài 2 : Thực hiện phép tính :V
a) P =\(\frac{\frac{1}{5}-\frac{1}{9}+\frac{1}{13}}{\frac{9}{5}-1+\frac{9}{13}}+\frac{\frac{10}{7}-\frac{10}{11}-\frac{10}{17}}{\frac{12}{7}-\frac{12}{11}-\frac{12}{17}}\)
b) Q = \(\frac{\frac{1}{14}-\frac{1}{30}-\frac{1}{46}}{\frac{2}{35}-\frac{2}{75}-\frac{2}{115}}:\frac{\frac{3}{8}-\frac{15}{17}+\frac{30}{31}}{\frac{1}{6}-\frac{20}{51}+\frac{40}{93}}\)
giúp mình với
gấp gấp lắm
1/ tìm x
a) \(x.\left(x+\dfrac{2}{3}\right)=0\)
2/tìm giá trị nhỏ nhất của các biểu thức
a) \(\left|x+\dfrac{4}{6}\right|\)
b) \(\left|x-\dfrac{1}{3}\right|\)
3/ tính
a) \(\left(1+2+3+...90\right).\left(12.34-668\right):\left(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{6}\right)\)
b) \(\dfrac{\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}+\dfrac{\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}}{\dfrac{5}{4}-\dfrac{5}{6}+\dfrac{5}{8}}\)
a) 1+3-5-7+9+11-....-397-399
b) 1+2-3-4+5+6-....-99-100
c) 2-5+8-11+14-17+....+98-101
a) 1+3-5-7+9+11-......-397-399
b) 1+2-3-4+5+6-....-99+100
c) 2-5+8-11+14-17+....+98-101
giải nhanh giúp mình với ạ 1) TÍNH: a) -9/34: 17/4 ; b) 1/1/2(hỗn số) . 1/24 ; c) -5/2: 3/4 ; d) 4/1/5 : (-2/4/5) 2) TÍNH: a) 3/5 + (-4/3) + ( -3/4) ; b) -7/2 + ( -2/3) + (-3/5); c) 3/4 - [(-5/3) - (1/12 + 2/9)] 3) TÌM x : a) 11/12 - (2/5+x) = 2/3 4) a) ( -3/4 + 2/5 ) : 3/7 + ( 3/5 + -1/4 ) : 3/7 b) 7/8 : ( 2/9 - 1/18 ) + 7/8 : ( 1/36 - 5/12 )
