Question

(2/3*y-4/9)*[1/2+ (-3/7):y]=0.Tìm y nha

Các bác giupe nha

Answer 1

\(\left(\frac{2}{3}.y-\frac{4}{9}\right).\left[\frac{1}{2}+\left(-\frac{3}{7}\right):y\right]=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}\frac{2}{3}.y-\frac{4}{9}=0\\\frac{1}{2}+\left(-\frac{3}{7}\right):y=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{2}{3}\\x=\frac{6}{7}\end{array}\right.\)

Vậy  x = \(\frac{2}{3};\frac{6}{7}\)

Answer 2

\(\left(\frac{2}{3}y-\frac{4}{9}\right)\left[\frac{1}{2}+\left(-\frac{3}{7}\right):y\right]=0\)

\(\Leftrightarrow\)\(\frac{6y-4}{3}\left(\frac{1}{2}-\frac{3}{7y}\right)=0\)

\(\Leftrightarrow\)\(\left[\begin{array}{nghiempt}\frac{6y-4}{3}=0\\\frac{1}{2}-\frac{3}{7y}=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}6y-4=0\\-\frac{3}{7y}=-\frac{1}{2}\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}y=\frac{2}{3}\\7y=6\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}y=\frac{2}{3}\\y=\frac{6}{7}\end{array}\right.\)