\(\dfrac{x}{3}-\dfrac{1}{y}=1;xy-3=y;y\left(x-1\right)=3\)
\(\left\{{}\begin{matrix}y=\left\{-3;-1;1;3\right\}\\x-1=\left\{-1;-3;3;1\right\}\end{matrix}\right.\)
\(\left(x;y\right)=\left(0;-3\right);\left(-2;-1\right);\left(4;1\right);\left(2;3\right)\)