Với mọi x ta có :
\(\left|x+2\right|\ge0\)
\(\Leftrightarrow\left|x+2\right|+2019\ge2019\)
\(\Leftrightarrow\dfrac{2018}{\left|x+2\right|+2019}\le\dfrac{2018}{2019}\)
\(\Leftrightarrow M\le\dfrac{2018}{2019}\)
Dấu "=" xảy ra khi \(x=-2\)
Vậy \(M_{Max}=\dfrac{2018}{2019}\Leftrightarrow x=-2\)