\(1+3+5+7+...+99=\left(x-2\right)^2\)
\(\left(1+99\right)+\left(3+97\right)+\left(5+95\right)+...+\left(49+51\right)=\left(x-2\right)^2\)
\(100+100+100+...+100=\left(x-2\right)^2\)
\(100\cdot25=\left(x-2\right)^2\)
\(2500=\left(x-2\right)^2\)
\(\pm50^2=\left(x-2\right)^2\)
\(50=x-2\) hoặc \(-50=x-2\)
\(x=50+2\) hoặc \(x=-50+2\)
\(x=52\) hoặc \(x=-48\)
\(\left(1+99\right).49:100=2450\)