Câu hỏi của Hiền Tăng

Question

12|x-1|:3=43+23

Nguyễn Lê Phước Thịnh · Accepted Answer

Ta có: $12\cdot\left|x-1\right|:3=4^3+2^3$

$\Leftrightarrow\dfrac{12\left|x-1\right|}{3}=64+8=72$

$\Leftrightarrow4\left|x-1\right|=72$

$\Leftrightarrow\left|x-1\right|=18$

$\Leftrightarrow\left[{}\begin{matrix}x-1=18\x-1=-18\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=19\x=-17\end{matrix}\right.$

Vậy: $x\in\left\{19;-17\right\}$Câu trả lời: Ta có: $12\cdot\left|x-1\right|:3=4^3+2^3$

$\Leftrightarrow\dfrac{12\left|x-1\right|}{3}=64+8=72$

$\Leftrightarrow4\left|x-1\right|=72$

$\Leftrightarrow\left|x-1\right|=18$

$\Leftrightarrow\left[{}\begin{matrix}x-1=18\x-1=-18\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=19\x=-17\end{matrix}\right.$

Vậy: $x\in\left\{19;-17\right\}$

Trần Nguyên Đức · Answer

$12|x-1|:3=4^3+2^3$

$12|x-1|:3=64+8$

$12|x-1|:3=72$

$12|x-1|=72.3$

$12|x-1|=216$

$|x-1|=216:12$

$|x-1|=18$

$\Rightarrow x-1 \in \{18;-18\}$

$\Rightarrow x \in \{19;-17\}$

-Vậy $ x \in \{19;-17\}$Câu trả lời: $12|x-1|:3=4^3+2^3$