Tìm x
1) 2-3x=5x +10
2) 13-7x =4x-20
3) 11-9x =3 -7x
4) 5( 2x -3 ) - 4 ( 5x-7) = 19-2 ( x+11)
5) 4 ( x+3) -7x+17= 8( 5x -1)+166
6) 17-14(x+1)=13-4(x+1)-5(x-3)
7)5x-3,5+ ( 3x-4)
8) 7 (4x +3)- 4 (x-1)= 15 (x+0,75)+7
9) 3x -2,42 + 0,8= 3,38 - 0,2x
10) 9 ( x+3) + 6 = 4 ( 5x +9 )
Giải phương trình sau:
\(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{x+7}{15}\)
\(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
d) (5x+3) ( 4x-1) +(10x-7) (-2x+3) =27
e)(8x-5) (3x+2) -(12x+7) (2x-1)=17
f) (5x+9) (6x-1) -(2x-3)( 15z+1) = -190
g) 6x(5x+3) + 3x(1-10x) =7
h) (3x-3) (5 -21x) +(7x+4)(9x-5) =44\
i) (x+1)(x+2)(x-5)-x2 (x+8)=27
Câu 1 : Giải phương trình
a. 5(x-3)-4=2(x-1)
b. 5-(6-x)=4(3-2x)
c. (3x+5)(2x+1)=(6x-2)(x-3)
d. (x+2)2 + 2(x-4)=(x-4)(x-2)
Bài 2 : Giải phương trình
a) x/3 - 5x/6 - 15x/12 = x/4 - 5
b) 8x-3/4 - 3x-2/2 = 2x-1/2 + x+3/4
c) x-1/2 - x+1/15 - 2x-13/6 = 0
d) 3(3-x)/8 + 2(5-x)/3 = 1-x/2 - 2
e) 3(5x-2)/4 - 2 = 7x/3 - 5(x-7)
Bài 3 Giải phương trình
a) (5x-4)(4x+6)=0
b) (x-5)(3-2x)(3x+4)=0
c) (2x+1)(x2+2)=0
d) (8x-4)(x2+2x+2)=0
Bài 4 Giải phương trình
a) (x-2)(2x+3)=(x-1)(x-2)
b) (2x+5)(x-4)=(x-5)(4-x)
c) 9x2 -1 =(3x+1)(2x-3)
d) (x+2)2=9(x2-4x+4)
e)4(2x+7)2 -9(x+3)2 =0
Bài 5 Giải phương trình
a) (9x2 -4)(x+1)=(3x+2)(x2 -1)
b) (x-1)2 -1+x2 =(1-x)(x+3)
c) x4 +x3 3+x+1=0
Giải các phương trình sau
a) |x-2| = 3
b) |x+1| = |2x+3|
c) |3x| = x+6
d) |x-5| = 13-2x
e) |5x-1| = x-12
f) |-2x| = 3x+4
g) |2x-1| = 6-x
h) |-1+5x| = 8-x
i) |-2x+1| = x+3
k) |-2-5x| = -4x+7
sử dụng phương pháp đặt ẩn phụ
1, (x+1)(x+3)(x+5)(x+7) +15
Giải phương trình :
a) 1/x+1 - 5/x-2 = 15/(x+1)(2-x)
b) 1/x-1 - 3x2/x3 - 1 = 2x/x2 + x +1
c) x - 1/x+2 - x/x - 2 = 5x - 2/4 - x2
d) 7/8x + 5 - x/4x2 - 8x = x - 1/2x(x - 2) + 1/8x - 16
e) x + 5/x2 - 5x - x - 5/2x2 + 10x = x + 25/2x2 - 50
Giúp mình với
Tìm x, biết:
1) 2x (x-3) + 5x - 15 = 0
2) x ( 2x - 7) - 4x + 14 = 0
3) x2 - 12x + 36 = 0
4) (x + 3) (x2 - 3x + 9) - x (x -1)(x + 1) -27 = 0
Giải PT sau:
a, 3x - 7 = 0
b, 8 - 5x = 0
c, 3x - 2 = 5x + 8
d, \(\dfrac{3x-2}{3}\) = \(\dfrac{1-x}{2}\)
e, ( 5x + 1)(x - 3) = 0
f, (x + 1)(2x - 3) = 0
g, 4x(x + 3) - 5(x + 3) = 0
h, 8(x - 6) - 2x(6 - x) = 0
i, \(\dfrac{2}{x-1}\) + \(\dfrac{1}{x}\) = \(\dfrac{2x+5}{x^2-x}\)
k, \(\dfrac{3}{x+2}\) - \(\dfrac{2}{x-2}\) = \(\dfrac{2-x}{x^2-4}\)
m, \(\dfrac{3}{x}\) - \(\dfrac{2}{x-3}\) = \(\dfrac{4-x}{x^2-3}\)
n,\(\dfrac{3}{2x+10}\)+ \(\dfrac{2x}{x^2-25}\) = \(\dfrac{3}{x-5}\)
u, \(\dfrac{2}{x+3}\) - \(\dfrac{3}{x-2}\) = \(\dfrac{x+4}{\left(x+3\right)\left(x-2\right)}\)
