a: \(A=\dfrac{8}{7}+\dfrac{5}{49}+\dfrac{1}{11}=\dfrac{720}{539}\)
b: \(A=\dfrac{4\cdot13-4\cdot40}{27}=\dfrac{-27\cdot4}{27}=-4\)
c: \(=\dfrac{8}{3}\cdot\dfrac{3}{8}\cdot\dfrac{2}{5}\cdot10\cdot\dfrac{19}{92}\)
\(=4\cdot\dfrac{19}{92}=\dfrac{19}{23}\)
d: \(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=\dfrac{-5}{11}\)