Question

1. tìm x

a. x- \(\left(\dfrac{1}{3}\right)^3\)= \(\dfrac{-1}{3}\)

b. \(\left(\dfrac{4}{5}\right)^5.x=\left(\dfrac{4}{5}\right)^7\)

c. \(x+\left(\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)

d. \(\left(3x+1\right)^3=-27\)

Answer 1

a. x=-8/27
b. x=16/25
c. x=-3/16
d. x=-4/3

Answer 2

a: \(x=\dfrac{-1}{3}+\left(\dfrac{1}{3}\right)^3=\dfrac{-1}{3}+\dfrac{1}{27}=\dfrac{-9+1}{27}=\dfrac{-8}{27}\)

b: \(x=\left(\dfrac{4}{5}\right)^7:\left(\dfrac{4}{5}\right)^5=\left(\dfrac{4}{5}\right)^2=\dfrac{16}{25}\)

c: \(x=\dfrac{1}{16}-\dfrac{1}{4}=\dfrac{1}{16}-\dfrac{4}{16}=\dfrac{-3}{16}\)

d: =>3x+1=-3

=>3x=-4

=>x=-4/3