`1,[(-3).3+5]-26=-2x-3`
`=>(-9+5)-26=-2x-3`
`=>-4-26=-2x-3`
`=>-30=-2x-3`
`=>-2x=-27`
`=>x=27/2`
Vậy `x=27/2`
`2)-[(-35)-3]=2x-2`
`=>-(-38)=2x-2`
`=>38=2x-2`
`=>2x=40`
`=>x=20`
Vậy `x=20`
1) \(\left[\left(-3\right)\cdot3+5\right]-26=-2x-3\\ \Rightarrow-9+5-26=-2x-3\\ \Rightarrow-2x=-9+5-26+3\\ \Rightarrow-2x=-27\\ \Rightarrow x=\dfrac{27}{2}\)
Vậy \(x=\dfrac{27}{2}\)
2) \(-\left[\left(-35\right)-3\right]=2x-2\\ \Rightarrow2x-2=-\left(-38\right)\\ \Rightarrow2x=38+2\\ \Rightarrow2x=40\\ \Rightarrow x=20\)
Vậy \(x=20\)
1) Ta có: \(\left[\left(-3\right)\cdot3+5\right]-26=-2x-3\)
\(\Leftrightarrow-2x-3=-4-26\)
\(\Leftrightarrow-2x-3=-30\)
\(\Leftrightarrow-2x=-27\)
hay \(x=\dfrac{27}{2}\)
Vậy: \(x=\dfrac{27}{2}\)
2) Ta có: \(-\left[\left(-35\right)-3\right]=2x-2\)
\(\Leftrightarrow2x-2=-\left(-38\right)\)
\(\Leftrightarrow2x-2=38\)
\(\Leftrightarrow2x=40\)
hay x=20
Vậy: x=20
1,[(−3).3+5]−26=−2x−31,[(-3).3+5]-26=-2x-3
⇒(−9+5)−26=−2x−3⇒(-9+5)-26=-2x-3
⇒−4−26=−2x−3⇒-4-26=-2x-3
⇒−30=−2x−3⇒-30=-2x-3
⇒−2x=−27⇒-2x=-27
⇒x=272⇒x=272
Vậy x=272x=272
2)−[(−35)−3]=2x−22)-[(-35)-3]=2x-2
⇒−(−38)=2x−2⇒-(-38)=2x-2
⇒38=2x−2⇒38=2x-2
⇒2x=40⇒2x=40
⇒x=20⇒x=20
Vậy x=20
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