Question

1. 16x ( 2 - x ) - ( 4x - 5 ) bình phương = 0

2. ( x - 7 ) bình phương + 3 = ( x - 2 ) ( x + 2 )

3. ( 2x - 3 ) bình phương - ( 7x - 2x ) bình = 2

4. ( 5x - 7 ) bình - ( 1- 3x ) bình = 16x ( x - 3 )

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Answer 1

1) \(16x\left(2-x\right)-\left(4x-5\right)^2=0\)

\(32x-16x^2-16x^2+40x-25=0\)

\(72x-16x^2-25=0\)

Đề sai ko bạn

2) \(\left(x-7\right)^2+3=\left(x-2\right)\left(x+2\right)\)

\(\left(x^2-14x+7\right)+3-\left(x-2\right)\left(x+2\right)=0\)

\(x^2-14x+7+3-x^2+4=0\)

\(-14x+14=0\)

\(x=1\)

3) \(\left(2x-3\right)^2-\left(7x-2x\right)^2=2\)

\(\left(2x-3\right)^2-\left(5x\right)^2=2\)

\(\left(2x-3-5x\right)\left(2x-3+5x\right)=2\)

\(\left(-3x-3\right)\left(7x-3\right)=2\)

=> lập bảng tìm x

4) \(\left(5x-7\right)^2-\left(1-3x\right)^2=16x\left(x-3\right)\)

\(25x^2-70x+49-9x^2+6x-1-16x^2+48x=0\)

\(-16x+48=0\)

\(x=3\)