Question

Answer 1

Câu 144 : 

Coi n A = 1(mol)

n O2 = a(mol) ; n CO2 = b(mol)

Ta có: 

a + b = 1

32a + 44b = 1.18,4.2

=> a = 0,6 ; b = 0,4

%V O2 = 0,6/1  .100% = 60%
%V CO2 = 0,4/1  .100% =40%

Answer 2

Câu 145 :

Gọi n O2 = a(mol) ; n O3 = b(mol)

a) M A = 1,5.29 = 43,5

Ta có :32a + 48b = (a + b)43,5

<=> 11,5a = 4,5b

<=> a/b = 9/23

=> %V O2 = a/(a + b) .100% = 9/(9 + 23) .100% = 28,125%

%V O3 = 100%- 28,125% = 71,125%

b) M A = 1,4.28 = 39,2

=> 32a + 48b = 39,2(a + b)

<=> 7,2a = 8,8b<=> a/b = 11/9

%V O2 = a/(a + b) .100% = 11/(11 + 9) .100% = 55%

%V O3 = 100% -55% = 45%