Question

Answer 1

\(\dfrac{3}{x^2-5x}=\dfrac{3}{x\left(x-5\right)}=\dfrac{3.2}{2x\left(x-5\right)}=\dfrac{6}{2x\left(x-5\right)}\)

\(\dfrac{5}{2x-10}=\dfrac{5}{2\left(x-5\right)}=\dfrac{5.x}{2x\left(x-5\right)}=\dfrac{5x}{2x\left(x-5\right)}\)

Answer 2

\(\dfrac{3}{x^2-5x}và\dfrac{5}{2x-10}\)

\(x^2-5x=x\left(x-5\right)\)

\(2x-10=2\left(x-5\right)\)

MTC: \(2x\left(x-5\right)\)

\(\dfrac{3}{x^2-5x}=\dfrac{3.2}{\left(x^2-5x\right).2}=\dfrac{6}{2x\left(x-5\right)}\)

\(\dfrac{5}{2x-10}=\dfrac{5.x}{\left(2x-10\right).x}=\dfrac{5x}{2x\left(x-5\right)}\)

Answer 3

ta có 

`x^2-5x=x(x-5)`

`2x-10= 2x(x-5)`

`NTP: 2; 1`

Quy đồng :

`3/(x^2-5x)=(3.2)/((x^2-5x).2)=6/(2x(x-5))`

`5/(2x-10)=(5.1)/((2x-10).1)=5/(2x(x-5))`