Question

Answer 1

Answer 2

Có : \(A=\dfrac{2x-3}{x+1}=\dfrac{2x+2-5}{x+1}=\dfrac{2\left(x+1\right)-5}{x+1}=2-\dfrac{5}{x+1}\)

Để A có giá trị nguyên ⇔ x + 1 ∈ Ư(5) = \(\left\{\pm1;\pm5\right\}\)

⇒ \(x\in\left\{0;-4;2;6\right\}\)