Bài 7:
a: \(\Leftrightarrow\dfrac{39}{7}:x=13\)
nên \(x=\dfrac{39}{7}:13=\dfrac{39}{7}\cdot\dfrac{1}{13}=\dfrac{3}{7}\)
b: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{5}{12}\)
hay x=5/2
c: \(\Leftrightarrow x=\dfrac{13}{12}\cdot\dfrac{46}{15}=\dfrac{299}{90}\)
d: \(\Leftrightarrow x\cdot\left(\dfrac{3}{4}+\dfrac{2}{5}\right)=1\)
\(\Leftrightarrow x\cdot\dfrac{23}{20}=1\)
hay x=20/23