PTHH: \(Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\)
a+b) Ta có: \(n_{Zn}=\dfrac{13}{65}=0,2\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{HCl}=0,4\left(mol\right)\\n_{H_2}=0,2\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_{HCl}=0,4\cdot36,5=14,6\left(g\right)\\V_{H_2}=0,2\cdot22,4=4,48\left(l\right)\end{matrix}\right.\)
c) PTHH: \(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
Ta có: \(\left\{{}\begin{matrix}n_{H_2}=0,2\left(mol\right)\\n_{Fe_2O_3}=\dfrac{16}{160}=0,1\left(mol\right)\end{matrix}\right.\)
Xét tỉ lệ: \(\dfrac{0,1}{1}>\dfrac{0,2}{3}\) \(\Rightarrow\) H2 p/ứ hết, Fe2O3 còn dư
\(\Rightarrow\) Dùng lượng Hidro không thể khử hết 16 gam Sắt (III) oxit