\(A=cos^213^o+sin^213^o+cos^22^o+sin^288^o-\dfrac{tan40^o}{tan40^o}\)
\(A=1+1-1=1\)
b)
có \(sin^2\alpha+cos^2\alpha=1\)
\(cos^2\alpha=1-\left(\dfrac{4}{5}\right)^2\)
\(cos^2\alpha=\dfrac{9}{25}=>cos\alpha=\dfrac{3}{5}\)
\(tan\alpha=\dfrac{sin\alpha}{cos\alpha}=\dfrac{4}{\dfrac{5}{\dfrac{3}{5}}}=\dfrac{4}{3}\)
cot\(\alpha=\)3/4